Assignment Details

WOWZERS!!! I just thought up an excellent question using v2 = u2+2as... see Additional Info

2023-2024

10EF/Ph - DA - Mr Russell (Tue & Wed)

Date Due

May 15, 2024

Additional Info
In Q1cii of the questions you were doing today in class, you should have found that the distance travelled from the area under the graph is 270m. If you want, you can try to verify this by using the equation v^2 = u^2 + 2as...
ie: Plug in your known values of v, u and a that you found from the graph, then rearrange the equation to verify that s = 270 m.

I'm a genius!!!